wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the combustion of 1 mole of a liquid benzene at 25oC, the enthalpy is given by:
C6H6(l)+152O2(g)6CO2(g)+3H2O(l) ΔH=780980 cal
What would be the internal energy of the reaction?

A
780 kcal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
780 kcal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
580 kcal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
580 kcal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 780 kcal
We know. ΔH=ΔU+ngRT
where H and U are the enthalpy and the internal energy of a reaction.
Δng = difference in moles of gaseous products and reactants = 6152 = 32 = -1.5
ΔU=ΔHngRT = 780980(1.5)×2×298
ΔU=780086 cal = 780 kcal


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon