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Question

For the combustion of 1 mole of a liquid benzene at 25oC, the enthalpy is given by:
C6H6(l)+152O2(g)6CO2(g)+3H2O(l) ΔH=780980 cal
What would be the internal energy of the reaction?

A
780 kcal
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B
780 kcal
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C
580 kcal
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D
580 kcal
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Solution

The correct option is B 780 kcal
We know. ΔH=ΔU+ngRT
where H and U are the enthalpy and the internal energy of a reaction.
Δng = difference in moles of gaseous products and reactants = 6152 = 32 = -1.5
ΔU=ΔHngRT = 780980(1.5)×2×298
ΔU=780086 cal = 780 kcal


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