For the combustion of C 3 H 8 g at constant temperature - H - U is-A- - RTB- - RTC- -3 RTD- -3 RT

The correct option is C 3RTC_3 H_8 (g) + 5O_2 (g) → 3CO_2 (g) + 4H_2O (l) Δ U = q+w Δ H = Δ U +Δ n_gRT nbsp; (Δ H Δ U) = 3RT, ∵Δ n_g= 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sucrose

For the combu...

Question

For the combustion of $C_{3} H_{8} (g)$ at constant temperature $Δ H - Δ U$ is:

- R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3 R T

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 3 R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

The difference in the heat of reaction at constant volume and at constant pressure for the given reaction is:

$C H_{4} (g) + O_{2} (g) M n^{2 +} - -- \to H C O O H (l) + H_{2} (g)$

Δ U

C H_{4} (g)

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)

- 393 k J m o l^{- 1}

Δ H

C_{3} H_{8 (g)} + 5 O_{2 (g)} ⇌ 3 C O_{2 (g)} + 4 H_{2} O_{(l i q)}

Δ H - Δ E

For the reaction, N₂ + 3H₂ ⇌ 2NH₃, ∆H= …………….

∆U° of combustion of CH4 (g)at certain temperature is -393kj/ mol.Then value of ∆H° is

1)0

2)<∆U°

3)>∆U°

4)=∆U°

Join BYJU'S Learning Program