For the combustion of C 3 H 8 g at constant temperature - H - U is-A- - RTB- - RTC- -3 RTD- -3 RT

The correct option is C 3RTC_3 H_8 (g) + 5O_2 (g) → 3CO_2 (g) + 4H_2O (l) Δ U = q+w Δ H = Δ U +Δ n_gRT nbsp; (Δ H Δ U) = 3RT, ∵Δ n_g= 3 ...

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Sucrose

For the combu...

Question

For the combustion of $C_{3} H_{8} (g)$ at constant temperature $Δ H - Δ U$ is:

- R T

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+ R T

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- 3 R T

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+ 3 R T

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The difference in the heat of reaction at constant volume and at constant pressure for the given reaction is:

$C H_{4} (g) + O_{2} (g) M n^{2 +} - -- \to H C O O H (l) + H_{2} (g)$

Δ U

C H_{4} (g)

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)

- 393 k J m o l^{- 1}

Δ H

C_{3} H_{8 (g)} + 5 O_{2 (g)} ⇌ 3 C O_{2 (g)} + 4 H_{2} O_{(l i q)}

Δ H - Δ E

For the reaction, N₂ + 3H₂ ⇌ 2NH₃, ∆H= …………….

∆U° of combustion of CH4 (g)at certain temperature is -393kj/ mol.Then value of ∆H° is

1)0

2)<∆U°

3)>∆U°

4)=∆U°

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