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Question

For the complete combustion of ethanol, C2HsOH(l)+3O2(g)+2CO2+2H2O(l) the amount of heat produced as measured inthe bomb calorimeter is 1364.47 kJ mol1 at 25C. Assuming ideality, the enthalpy of combustion ΔcH for the reaction will be [ R = 8.314 JK1mol1 ]


A

1366.95kJmol1

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B

1361.95kJmol1

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C

1460.50kJmol1

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D

1350.50kJmol1

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Solution

The correct option is A

1366.95kJmol1


C2H5OH(l)+3O2(g)+2CO2+3H2O(l)

Amount of heat produced in the bomb calorimeter = ΔU =- 1364.47 kJ mol1

Enthalpy of a combustion reaction is: ΔH=ΔU+ΔngRT

Where , Δ U = internal energy

Δng = moles of gas (products -reacants), R = Gas constant=, T = Temperature in K

As per the equation,

Δng=23=1

T=25C=25+273K

T=298K

Thus, ΔH=1364.47+[(1)×8.314×2981000]

ΔH=1364.472.477=1366.947 kJ mol1

Hence, they enthalpy of combustion , ΔcH for the given reaction will be - 1366.95 kJ mol1


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