You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polarity and Dipole Moments

For the compo...

Question

For the compound $C H_{3} C l, C H_{3} B r, C H_{3} I, C H_{3} F$ , the correct order of increasing C-X bond length where X is the halogen is :

C H_{3} F > C H_{3} C l > C H_{3} B r > C H_{3} I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} F > C H_{3} B r > C H_{3} C l > C H_{3} I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} F < C H_{3} I < C H_{3} B r < C H_{3} C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C l < C H_{3} B r < C H_{3} F < C H_{3} I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C H_{3} F > C H_{3} C l > C H_{3} B r > C H_{3} I$
Increase in size of the atom increases the bond length. Hence the order of bond length is
C−F<C−Cl<C−Br<C−I

Suggest Corrections

Similar questions

C H_{3} C l, C H_{3} B r, C H_{3} I

C H_{3} F

Compare the dipole moment of the following.

CH₃F,CH₃Cl,CH₃Br, CH3 I.

{C H}_{3} O H

S_{N} 2

{C H}_{3} O H

{C H}_{3} F

{C H}_{3} C l

{C H}_{3} B r

{C H}_{3} I

{C H}_{3} O {S O}_{2} {C F}_{3}

^{14} {C H}_{3} O H

Which has highest bond dissociation energy?

CH3F. CH3Cl . CH3Br. CH3I

PLS EXPLAIIN IN DETAIL ans is ch3F

MY opinion ch3I coz in ch3F F is more electronegativity so it has pulled electrons therefore it is easier to break the bond

And CH3I. I will nt attract electron compared to F

S N^{2}

O H^{-}

C H_{3} B r

C H_{3} I

(C H_{3})_{3} C C l

C H_{3} C l

Join BYJU'S Learning Program