For the curve corresponding to f x - x 2-8 x -12- find the point at which the tangent is parallel to the x axisA- -4-4B- -1-1C- 1-1D- 4-4

The correct option is D (4, 4) ...

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Rolle's Theorem

For the curve...

Question

For the curve corresponding to f(x) = x² - 8x + 12, find the point at which the tangent is parallel to the x axis

(4,-4)

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(-4,4)

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(-1,1)

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(1,1)

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Solution

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Similar questions

\frac{x^{2}}{4} + \frac{y^{2}}{25} = 1

f (x) = \frac{x^{2} - 1}{x^{2} + 1}, x \in R

f (x) = \sqrt{x^{2} - 4}

[2, 4]

y^{2} = 4 x,

y = 2 x + 4

Find points on the curve $\frac{x^{2}}{9} + \frac{y^{2}}{16} = 1$ at which the tangents are

(a) parallel to X-axis

(b) parallel to Y-axis.

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