Parametric equations are
x=t2+t ⋯(1)y=t2−t ⋯(2)
From (1)+(2), we get
x+y2=t2 ⋯(3)
From (1)−(2), we get
x−y2=t ⋯(4)
Now from (3) and (4), we have
x+y2=(x−y2)2⇒x2+y2−2xy−2x−2y=0
Comparing the above equation with general form of conic equation, we get
a=b=1,h=−1,g=f=−1,c=0
∴Δ=0−2−1−1−0=−4⇒|Δ|=4