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Question

For the curve x=a(cost+log(tant2)),y=asint, the length of the subtangent is

A
|atant|
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B
|acott|
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C
|a|
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D
|acost|
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Solution

The correct option is D |acost|
Given, y=asint
dydt=acost .....(1)
Also given, x=a(cost+logtant2)
dxdt=a(sint+12sec2t2tant2)
dxdt=a(sint+1sint)
dxdt=a(sin2t+1sint)
dxdt=acos2tsint ---- Equation 2
Now, dxdy=dxdtdydt
dxdy=acos2tsintacost (Using (1) and (2))
dxdy=costsint
Length of subtangent =|ydxdy|
=|asint×costsint|
=|acost|

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