For the curve y = 3sin θcosθ,x=eθsinθ,0≤θ≤π; tangent is parallel to x-axis, then θ =
A
\N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
π6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cπ4 Given y = 3 sin θcosθ, x = eθsinθ
For tangent parallel to x-axis, we should have dydx = 0 ⇒dydx = 0 and dxdθ≠0 and ddθ(3sin2θ2) = 0 ⇒3cos2θ=0⇒2θ=π2 ⇒θ=π4
Note that for θ=π4,dxdθ=eθ[sinθ+cosθ]≠0.