Question

For the decolorisation of $1mole$ of $KMn{O}_4$, the number of moles of $H_2{O}_2$ required is

• A. $1/2$
• B. $3/2$
• C. $5/2$
• D. $7/2$

Answer 1

Answer: (A), (C)

The correct options are
A $1/2$
C $5/2$

Balanced equation of decolorization of $KMn{O}_4$
$2KMn{O}_4+5H_2{O}_2+3H_{2}S{O}_4\to K_{2}S{O}_4+2MnS{O}_4+8H_{2}O+5O_2$
From the equation we say that 2 moles of $KMn{O}_4$ is decolorized by 5 moles $H_2{O}_2$.
So 1 mole of $KMn{O}_4$ is decolorized by 5/2 moles $H_2{O}_2$.
Hence option C is orrect.