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Percentage Composition

For the decom...

Question

For the decomposition of $H I$ at $1000$ $K$ $(2 H I ⟶ H_{2} + I_{2})$ , the following data were obtained:
$[H I] (M)$ Rate of decomposition of $H I (m o l L^{- 1} s^{- 1})$
$0.1$ $2.75 \times 10^{- 8}$
$0.2$ $11 \times 10^{- 8}$
$0.3$ $24.75 \times 10^{- 8}$
The order of reaction is:

A

1

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B

2

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C

0

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D

1.5

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Solution

The correct option is B $2$
Rate $= k {[H I]}^{n}$
$11 \times 10^{- 8} = k {[0.2]}^{n}$ ...(i)
$2.75 \times 10^{- 8} = k {[0.1]}^{n}$ ....(ii)
Dividing equation (i) by equation (ii),
$4 = 2^{n}, n = 2$

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