Question

For the decomposition of ${\mathrm{N}}_2{\mathrm{O}}_5$ it is given that:

$\underset{\mathrm{Dinitrogen}\mathrm{pentaoxide}}{\underbrace{2{\mathrm{N}}_2{\mathrm{O}}_5\left(\mathrm{g}\right)}}\to \underset{\mathrm{Nitrogen}\mathrm{dioxide}}{\underbrace{4{\mathrm{NO}}_2\left(\mathrm{g}\right)}}+\underset{\mathrm{Oxygen}}{\underbrace{{\mathrm{O}}_2\left(\mathrm{g}\right)}}$, Activation energy $\mathrm{Ea}$

$\underset{\mathrm{Dinitrogen}\mathrm{pentaoxide}}{\underbrace{{\mathrm{N}}_2{\mathrm{O}}_5\left(\mathrm{g}\right)}}\to \underset{\mathrm{Nitrogen}\mathrm{dioxide}}{\underbrace{2{\mathrm{NO}}_2\left(\mathrm{g}\right)}}+\underset{\mathrm{Oxygen}}{\underbrace{\frac{1}{2}{\mathrm{O}}_2\left(\mathrm{g}\right)}}$, Activation energy ${\mathrm{Ea}}^{\text{'}}$then,

• A. $\mathrm{Ea}={\mathrm{Ea}}^{\text{'}}$
• B. $\mathrm{Ea}>{\mathrm{Ea}}^{\text{'}}$
• C. $\mathrm{Ea}<{\mathrm{Ea}}^{\text{'}}$
• D. $\mathrm{Ea}=2{\mathrm{Ea}}^{\text{'}}$

Answer 1

The correct option is A

$\mathrm{Ea}={\mathrm{Ea}}^{\text{'}}$

The explanation for the correct answer:

Option (A) $\mathrm{Ea}={\mathrm{Ea}}^{\text{'}}$:

Activation energy:

1. The activation energy is the least amount of energy needed to start a chemical reaction.
2. The energy of the electrons and nuclei as the reaction progresses to its products determines the activation energy.
3. The stoichiometric coefficients have no impact on the activation energy.
4. Because the activation energy of both reactions is independent of their concentration, their activation energies are equal.

Therefore, Option (A) is the correct answer.