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Question

For the decomposition of ozone in oxygen
O3(g)O2(g)

A
ΔrH=ve
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B
ΔrS=ve
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C
ΔrG=ve at only low temperature
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D
ΔrG=ve at only high temperature
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Solution

The correct option is A ΔrH=ve

O3(g)O2(g)
as O2 is more stable than O3
(Refer to Image)
Therefore the product will have lesser energy than the reactant. Hence on formation of product the energy will release and the reaction will be exothermic.
Therefore, ΔH= negative.

1074030_995969_ans_227552dbf0e641299b57f2b1b271d65e.PNG

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