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Sulphuric Acid

For the detec...

Question

For the detection of phosphorus, the organic compound after fusion with $N a_{2} O_{2}$ is extracted with water, boiled with $H N O_{3}$ and then ammonium molybdate added to it. A yellow precipitate is obtained which is due to the formation of:

A

ammonium phosphate

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B

ammonium phosphomolybdate

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C

ferric phosphate

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D

disodium ammonium phosphate

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Solution

The correct option is B ammonium phosphomolybdate
Correct answer : (B)
$N a_{3} P O_{4} + 3 H N O_{3} \to H_{3} P O_{4} + 3 N a N O_{3}$

$H_{3} P O_{4} + 12 (N H_{4})_{2} M o O_{4} A m m o n i u m M o l y b d a t e + 21 H N O_{3} \to (N H_{4})_{3} P O_{4} 12 M o O_{3} A m m o n i u m P h o s p h o M o l y b d a t e + 21 N H_{4} N O_{3} + 12 H_{2} O$

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