Question

For the diagram shown above, the area of $\Delta ABC=$

• A. $40{\text{cm}}^2$
• B. $80{\text{cm}}^2$
• C. $20{\text{cm}}^2$

Answer 1

The correct option is A $40{\text{cm}}^2$

For $\Delta ABC$ we need to find its area.
We know area of a triangle $=\frac{1}{2}\times \text{Base}\times \text{Height}$
For this triangle, we need to find the base and its corresponding
height.
Here, we can take $AB$ as one of the base, then $CP$ will be its height.
$\therefore$ Area $\Delta ABC=\frac{1}{2}\times AB\times CP$
$=\frac{1}{2}\times 8\times 10=40{\text{cm}}^2$