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Byju's Answer
Standard XII
Mathematics
Logarithmic Differentiation
For the diffe...
Question
For the differential equation
d
y
d
t
+
5
y
=
0
with y(0) = 1, the general solution is
A
e
5
t
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B
e
−
5
t
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C
5
e
−
5
t
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D
e
√
−
5
t
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Solution
The correct option is
B
e
−
5
t
d
y
d
t
+
5
y
=
0
....(i)
⇒
d
y
y
=
−
5
d
t
Using variable seperable method
⇒
l
o
g
y
=
−
5
t
+
l
o
g
c
⇒
l
o
g
(
y
c
)
=
−
5
t
⇒
y
=
c
e
−
5
t
...(ii)
Using y(0) = 1, we get c = 1
∴
The solution is y =
e
−
5
t
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2
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