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Question

For the differential equation dydt+5y=0 with y(0) = 1, the general solution is

A
e5t
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B
e5t
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C
5e5t
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D
e5t
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Solution

The correct option is B e5t
dydt+5y=0 ....(i)

dyy=5dt
Using variable seperable method

logy=5t+logc

log(yc)=5t

y=ce5t ...(ii)

Using y(0) = 1, we get c = 1

The solution is y = e5t

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