For the differential equation in given question find the general solution.
dydx=(1+x2)(1+y2)
Given, dydx=(1+x2)(1+y2)
On separating the variables, we get
dy1+y2=dx(1+x2)⇒dy1+y2=1dx+x2dx
Integrating, we get ∫dy1+y2=∫dx+∫x2dx⇒tan−1y=x+x33+C
which is required general solution.