wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

For the differential equation in given question find the general solution.

dydx=1cosx1+cosx

Open in App
Solution

Given, dydx=1cosx1+cosx
On separating the variables and integrating, we get
dy=1cosx1+cosxdxy=2sin2(x/2)2cos2(x/2)dx [1cosx=2sin2(x/2) and 1+cosx=2cos2(x/2)]y=tan2(x/2)dx (1+tan2x2=sec2x2)y=(sec2(x/2)1)dxy=sec2(x/2)dx1dxy=2tanx2x+C. (sec2xdx=tanx)
which is the required general solution.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon