For the discontinuous function given below, find the value of $f (- 3)$ .
$f (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} x^{2} + 1, i f x < 0 \frac{2 x}{3} - 1, i f 0 < x < 3 4 - x, i f x > 3 \end{matrix}$

-3

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-3, 7, and 10

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Solution

The correct option is C 10
The function is of the form $x^{2} + 1$ when $x < 0$
Since we need the value of the function at $x = - 3$ , we substitute $x = - 3$ to get
$f (- 3) = (- 3)^{2} + 1 = 10$

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