For the disproportionation of copper - 2 Cu- - Cu -2 -Cu- E - is- Given- E for Cu-2- Cu is 0-34 V and E for Cu-2- Cu- is 0-15 V

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For the dispr...

Question

For the disproportionation of copper :
$2 C u^{+} \to {C u}^{+ 2} + C u, E^{\circ}$ is:
Given;
$E$ for $C u^{+ 2}$ / $C u$ is $0.34 V$ and
$E$ for $C u^{+ 2}$ / $C u^{+}$ is $0.15 V$

0.49 V

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0.19 V

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0.38 V

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- 0.38 V

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Similar questions

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15 V

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34 V

E^{o}

C u^{+} + e^{-} \to C u

C u^{+}

C u^{+}

E^{o}

C u^{+}

(E_{C u^{2 +} / C u^{+}}^{o} = + 0.153 V, E {^{o}}_{C u^{+} / C u} = 0.53 V)

{C u}^{+} (a q)

2 {C u}^{+} (a q) ⇌ {C u}^{2 +} (a q) + C u (s)

E^{o}

E_{{C u}^{2 +} / C u}^{o} = 0.34 V

E_{{C u}^{2 +} / {C u}^{+}}^{o} = 0.15 V

C u^{+}

E^{0} for C u^{+}

E_{C u^{2 +} / C u^{+}}^{0} = + 0.15 V E_{C u^{+} / C u}^{0} = 0.53 V

C u^{+}

E^{\circ}

C u^{+}

E^{\circ} C u^{2} / C u = 0.34 V)

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