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Question

For the dissociation of PCl5(g)
PCl5(g)PCl(g)+Cl2(g)
Slope of the linear curve is such that θ=tan1(2.1)

Thus, Ho is

A
28.72 J mol1
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B
28.72 J mol1
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C
40.2 J mol1
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D
12.47 J mol1
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Solution

The correct option is C 40.2 J mol1
Van't Hoff equation is
log10K=Ho2.303 RT+logC
where C is a constant.
Graph between log10K and 1T is linear.
On comparing it to
y=mx+c
slope, m=Ho2.303 R .....1
but, slope m also equals,tan θ
since θ=tan1(2.1)
So,
slope, m=tan θ=2.1 ......2
comparing equation 1 and 2 , we get
Ho2.303 R=tan θ

putting the values we get,
Ho=2.303 R×2.1
=2.303×8.314×2.1=40.2 J mol1.

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