Question

For the electrochemical cell $M|M^{+}\parallel X^{-}|X$, $E_{\left(M^{+}|M\right)}^o=0.44V$ and $E_{\left(X|X^{-}\right)}^o=0.33V$. From this data one can deduce that:

If $0.5amp$ current is passed through acidified silver nitrate.

• A. $M+X\to M^{+}+X^{-}$ is the spontaneous reaction
• B. $M^{+}+X^{-}\to M+X$ is the spontaneous reaction
• C. $E_{cell}=0.77V$
• D. $E_{cell}=-0.77V$

Answer 1

Answer: (B)

$M^{+}+X^{-}\to M+X$ is the spontaneous reaction

$M^{+}+X\to M+X$ is spontaneous because for the cell represented by $M|M^{+}\parallel X^{-}|X$, the value of $E^o$ is positive i.e., $(0.44-0.33)V=0.11V$