For the elementary reaction M ⟶ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

(IIT-JEE-Advanced 2014)

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Solution

The correct option is B 3
$r_{1} = K [M]^{x}$

$8 r_{1} = K [2 M]^{x}$ …(ii)
$\Rightarrow \frac{1}{8} = (\frac{1}{2})^{x} \Rightarrow (\frac{1}{2})^{3} = (\frac{1}{2})^{x} \Rightarrow x = 3.$

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Similar questions

For the elementary reaction M ⟶ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

(IIT-JEE-Advanced 2014)

For the elementary reaction M ⟶ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

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Q. For the elementary reaction

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, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is:

For the elementary reaction $M ⟶ N$ , the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is:

For the elementary reaction, $M \to N$ , the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

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For the elementary reaction M ⟶ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is (IIT-JEE-Advanced 2014)

The correct option is B 3r1=K[M]x 8r1=K[2M]x …(ii) ⇒18=(12)x⇒(12)3=(12)x⇒x=3.

For the elementary reaction M ⟶ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

(IIT-JEE-Advanced 2014)

The correct option is B 3
$r_{1} = K [M]^{x}$

$8 r_{1} = K [2 M]^{x}$ …(ii)
$\Rightarrow \frac{1}{8} = (\frac{1}{2})^{x} \Rightarrow (\frac{1}{2})^{3} = (\frac{1}{2})^{x} \Rightarrow x = 3.$