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Question

For the equation 3x2+px+3=0, the roots are real and 1 root is the square of the other, Find p?


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Solution

Step 1: Form the equation

The given equation is 3x2+px+3=0

where a=3,b=p and c=3

Let us assume the roots of the given equation are y and y2.

As per the given equation

Sum of the roots -ba is

(y+y2)=-p3…………………….(1)

Product of the roots ca is

y3=1

⇒y=1

Step 2: Calculate p

Substituting the value of y on equation (1),

1+1=-p3

⇒p=-6

Hence the value of p is -6.


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