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Question
For the equation 3x2 + px + 3 = 0, the roots are real and 1 root is the square of the other, Find p?
For the equation 3x2 + px + 3 = 0, the roots are real and 1 root is the square of the other, Find p?
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Solution
The correct option is C -6
Let roots of the given equation are a and a2.
Sum of the roots (a + a2) = - P/3 .........................(1)
Product of the roots (a)3 = 1 => a = 1
From equation (1),
1 + 1 = - P/3 => P = - 6
Alternatively: - 1, 1 be the roots. Eqn. becomes x2 - 2x + 1 = 0 or 3 x2 - 6x + 3 = 0.
Let roots of the given equation are a and a2.
Sum of the roots (a + a2) = - P/3 .........................(1)
Product of the roots (a)3 = 1 => a = 1
From equation (1),
1 + 1 = - P/3 => P = - 6
Alternatively: - 1, 1 be the roots. Eqn. becomes x2 - 2x + 1 = 0 or 3 x2 - 6x + 3 = 0.
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