For the equation (x+1x)2ā5(x+1x)+6=0,
two roots are rational, two roots are irrational
Let x+1x=y
Given equation is y2−5y+6=0
(y - 2) (y - 3) = 0
y = 2, y =3
x2−2x+1=0x=23,32∣∣∣x2−3x+1=0x=3±√9−42=3±√52
Equation has two roots rational two roots irrational.