For the equation |x|2+|x|−6=0,the sum of the real roots is
1
0
2
none of these
Let p = |x|⇒ p2+p−6=0⇒p2+3p−2p−6=0⇒(p+3)(p−2)=0⇒p=−3,2Also,|x|=p⇒|x|=2, or |x|=−3Modulus can not be negative,∴|x|=2⇒x=±2⇒x=2 or −2Sum of the roots of x is 0.
Nature of roots of x−2x−1=x+42x+2 is