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Question

For the equilibrium 2NOCl give 2NO+Cl2. The value of k=3.75×10^-6 at 1069 k. Calculate kp at this temperature (R=0.083 bar litre per k per mol

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Solution

(b)For the equilibrium

The relation between Kp and Kc is given as:
Kp = Kc (RT)Δ n

From reaction :
Δn = 3 – 2 = 1
R = 0.0831 bar Lmol–1K–1
T = 1069 K
Kc = 3.75 X 10-6

Formula used :
Kp = Kc (RT) Δ n

Kp = 3.75 x 10-6 (0.0831 x 1069)1
Kp = 333.12 x 10-4 Answer


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