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Byju's Answer
Standard VIII
Chemistry
Collision Theory
For the equil...
Question
For the equilibrium,A(g) gives B(g), delta is -40kJ/mol. If the ratio of the activation energies of the forward (Ef) and reverse (Eb) rxn is 2/3 then :(in kj/mol)
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Similar questions
Q.
For the equilibrium,
A
(
g
)
⇌
B
(
g
)
,
△
H
is
−
40
k
J
/
m
o
l
. If the ratio of the activation energies of the forward
(
E
f
)
and reverse
(
E
b
)
reactions is
2
/
3
then:
Q.
For the equilibrim,
A
(
g
)
⇌
B
(
g
)
,
Δ
H
=
−
40
k
J
/
m
o
l
. If the ratio of the activation energies of the forward
(
E
f
)
and reverse
(
E
b
)
reaction is
2
3
then:
Q.
The activation energy for the forward reaction
X
→
Y
is
60
k
J
m
o
l
−
1
and
Δ
H
is
−
20
k
J
m
o
l
−
1
. The activation energy for the reverse reaction is:
Q.
For a given reaction, energy of activation for forward reaction
(
E
a
f
)
is
80
k
J
/
m
o
l
.
Δ
H
=
−
40
k
J
/
m
o
l
for the reaction. A catalyst lowers
E
a
f
to
20
k
J
/
m
o
l
. The ratio of energy of activation for reverse reaction before and after addition of catalyst is:
Q.
If a reaction,
A
+
B
⟶
C
, is exothermic to the extent of
30
k
J
/
m
o
l
and the forward reaction has an activation energy of
249
k
J
/
m
o
l
, the activation energy for reverse reaction in
k
J
/
m
o
l
is:
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