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Question

For the equilibrium, A(g)B(g),H is 40 kJ/mol. If the ratio of the activation energies of the forward (Ef) and reverse (Eb) reactions is 2/3 then:

A
Ef=60 kJ/mol;Eb=100 kJ/mol
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B
Ef=30 kJ/mol;Eb=70 kJ/mol
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C
Ef=80 kJ/mol;Eb=120 kJ/mol
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D
Ef=70 kJ/mol;Eb=30 kJ/mol
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Solution

The correct option is D Ef=80 kJ/mol;Eb=120 kJ/mol
The given reaction is,
A(g)B(g)
H=40KJ/mol
& EfEb=23Ef=23Eb
From graph we have,
H=EbEf
40=Eb23Eb
40=13EbEb=120KJ/mol
& Ef=EbH
=120(40)
80 KJ/mol.

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