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Characteristics of Equilibrium Constant

For the equil...

Question

For the equilibrium, an increase of temperature will,

${2 N O}_{2} (g) ⇌ N_{2} O_{4} (g) + 14.6 k c a l$

favour the formation of

N_{2} O_{4}

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favour the decomposition of

N_{2} O_{4}

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not affect the equilibrium

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stop the reaction

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Solution

The correct option is B favour the decomposition of $N_{2} O_{4}$
The above reaction is endothermic, so increase in temperature will favor the reverse reaction. Therefore $N_{2} O_{4}$ will undergo decomposition.

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Similar questions

2 N O_{2} (g) ⇌ N_{2} O_{4} (g)

N_{2} O_{4}

N O_{2} (g)

N_{2} O_{4} (g)

N_{2} O_{4} (g) ⇌ 2 {N O}_{2} (g)

N_{2} O_{4}

77.70 g

N_{2} O_{4}

N_{2} O_{4} (g) \to 2 N O_{2} (g)

N_{2} O_{4}

N_{2} O_{4}

For the equilibrium $2 N O_{2} (g) ⇌ N_{2} O_{4} (g) + h e a t (14.6 k c a l)$ the increase in

temperature would

N_{2} O_{4}

{N O}_{2}

280 K

0.2

N_{2} O_{4}

2 \times 10^{- 3}

{N O}_{2}

2

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

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