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Standard XII

Chemistry

Characteristics of Equilibrium Constant

For the equil...

Question

For the equilibrium at $27^{o} C .$
$L i C l .3 N H_{3} (s) ⇌ L i C l . N H_{3} (s) + 2 N H_{3} (g); K_{P} = 9 a t m^{2}$
A 24.63 litre flask contain 1 mol $L i C l . N H_{3} .$ How many moles of $N H_{3}$ should be added to flask at this temperature to drive the backward reaction for completion.

5 moles

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8 moles

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3 moles

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2 moles

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Solution

The correct option is A 5 moles
Given: $K_{P} = 9 a t m^{2}$ = $P_{N H_{3}}^{2}$
$P_{N H_{3}} = 9 a t m^{2}$
$P_{N H_{3}} = 3 a t m$
Using, PV = nRT
$3 \times 24.63 = n_{N H_{3}} \times R \times 300$
$n_{N H_{3}} = 3$ (at equilibrium)
$L i C l .3 N H_{3} (s) ⇌ L i C l . N H_{3} (s) + 2 N H_{3} (g)$
1 n
0 n - 2
Now, we know, $n - 2 = 3$
n = 5 moles

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Similar questions

Q. For the equilibrium at

27^{o} C .

L i C l .3 N H_{3} (s) ⇌ L i C l . N H_{3} (s) + 2 N H_{3} (g); K_{P} = 9 a t m^{2}

A 24.63 litre flask contain 1 mol

L i C l . N H_{3} .

How many moles of

N H_{3}

should be added to flask at this temperature to drive the backward reaction for completion.

Q. For the equilibrium

L i C l . 3 N H_{3} (s) ⇌ L i C l . N H_{3} (s) + 2 N H_{3} (g);

K_{p} = 9 a t m^{2}

37^{\circ} C .

5 L

vessel contains

0.1

mole of

L i C l . N H_{3}

. How many moles of

N H_{3}

should be added to the flask at this temperature to derive the backward reaction for completion?
Use :

R = 0.082 {atm L mol}^{- 1} K^{- 1}

Q. For the equilibrium,

L i C l \cdot {3 N H}_{3} (s) ⇌ L i C l \cdot {N H}_{3} (s) + 2 {N H}_{3} (g)

K_{p} = 9 {a t m}^{2}

37^{o} C

5

litre vessel contains

0.1

mole of

L i C l \cdot {3 N H}_{3}

. How many moles of

{N H}_{3}

should be added to the flask at this temperature to derive the backward reaction for completion?

R = 0.082 a t m . L / m o l K

Q. For the equilibrium,

L i C l \cdot 3 N H_{3} (s) ⇌ L i C l \cdot N H_{3} (s) + 2 N H_{3} (g)

;

K_{p} = 9

a t m^{2}

37^{o}

C. A

5

litre vessel contains

0.1

mole of

L i C l \cdot N H_{3}

. How many moles of

N H_{3}

should be added to the flask at this temperature to derive the backward reaction for completion?
Use:

R = 0.082

atm-L/mol K

Q. For the equilibrium :

L i C l .3 {N H}_{3} (s) ⇌ L i C l .3 {N H}_{3} (s) + 2 {N H}_{3}

K_{p}

= 9

{a t m}^{2}

40 C

. A 5-L vessel contains 0.1 mole of

L i C l .3 N H_{3}

How many moles of

N H_{3}

should be added to the flask at this temperature to derive the backward reaction for completion?

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Characteristics of Equilibrium Constant

Standard XII Chemistry

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For the equilibrium at 27oC. LiCl.3NH3(s)⇌LiCl.NH3(s)+2NH3(g);KP=9 atm2 A 24.63 litre flask contain 1 mol LiCl.NH3. How many moles of NH3 should be added to flask at this temperature to drive the backward reaction for completion.

The correct option is A 5 moles Given: KP=9 atm2 = P2NH3 PNH3=9 atm2 PNH3=3 atm Using, PV = nRT 3×24.63=nNH3×R×300 nNH3=3 (at equilibrium) LiCl.3NH3(s)⇌LiCl.NH3(s)+2NH3(g) 1 n 0 n - 2 Now, we know, n−2=3 n = 5 moles

For the equilibrium at $27^{o} C .$
$L i C l .3 N H_{3} (s) ⇌ L i C l . N H_{3} (s) + 2 N H_{3} (g); K_{P} = 9 a t m^{2}$
A 24.63 litre flask contain 1 mol $L i C l . N H_{3} .$ How many moles of $N H_{3}$ should be added to flask at this temperature to drive the backward reaction for completion.