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Question

For the equilibrium at 27oC.
LiCl.3NH3(s)LiCl.NH3(s)+2NH3(g);KP=9 atm2
A 24.63 litre flask contain 1 mol LiCl.NH3. How many moles of NH3 should be added to flask at this temperature to drive the backward reaction for completion.

A
5 moles
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B
8 moles
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C
3 moles
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D
2 moles
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Solution

The correct option is A 5 moles
Given: KP=9 atm2 = P2NH3
PNH3=9 atm2
PNH3=3 atm
Using, PV = nRT
3×24.63=nNH3×R×300
nNH3=3 (at equilibrium)
LiCl.3NH3(s)LiCl.NH3(s)+2NH3(g)
1 n
0 n - 2
Now, we know, n2=3
n = 5 moles

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