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Arrhenius Acid

For the equil...

Question

For the equilibrium $C (s) + {C O}_{2} (g) ⇌ 2 C O (g)$ $K_{p} = 63 a t m$ at $1000 K$ . If at equilibrium $P_{C O} = 10 P_{{C O}_{2}}$ , then total pressure at equilibrium is-

6.30 a t m

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0.693 a t m

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6.93 a t m

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69.3 a t m

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Solution

The correct option is B $0.693 a t m$
$C (s) + C O_{2} (g) ⟶ 2 C O (g); K_{p} = 63$
$\Rightarrow K_{p} = \frac{P_{C O}^{2}}{P_{C O_{2}}} = \frac{(10 P_{C O_{2}})^{2}}{P_{C O_{2}}} = 100 P_{C O_{2}} = 63$
$\Rightarrow P_{C O_{2}} = \frac{63}{100} a t m = 0.63 a t m$
$\Rightarrow P_{C O} = 10 P_{C O_{2}} = 10 \times 0.63 a t m = 6.3 a t m$
$P_{t o t} = P_{C O_{2}} + P_{C O} = 0.63 a t m + 6.3 a t m = 6.9 a t m$ .

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