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Question

For the equilibrium N2+3H22NH3,Kc at 1000 K is 2.37×103. If at equilibrium [N2]=2M,[H2]=3M, the concentration of NH3 is:

A
0.00358 M
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B
0.0358 M
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C
0.358 M
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D
3.58 M
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Solution

The correct option is C 0.358 M
N2+3H22NH3

KE=2.37×103

[N2]=2m

[H2]=3m

[NH3]=?

KE=[NH3]2[N2][H2]3

2.37×103=[NH3]2[2][3]3

2.37×103=[NH3]22×27

[NH3]2=54×2.37×103

[NH3]2=12.79×102

[NH3]=12.79×102

[NH3]=0.0035M

Hence, the correct option is C

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