For the equilibrium $N H_{4} C l (s) ⇌ N H_{3} (g) + H C l (g), K_{p} = 16 {a t m}^{2}$ . The equilibrium pressure of the mixture is:

8

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4

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16

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32

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Solution

The correct option is A $8$
$K_{p} = P_{N H_{3}}^{'} \times P_{H C l}^{'} = 16$
$K_{p} = P \times P = 16$
$∴ P = 4$
$∴$ Total pressure at equilibrium $= P + P = 4 + 4 = 8$

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