Question

For the equilibrium of the reaction, $HgO\left(s\right)\rightleftharpoons Hg\left(g\right)+\frac{1}{2}{O}_2\left(g\right),K_p$ for the reaction at total pressure of P is ________.

• A. $K_p=\frac{2}{3^{3/2}}{p}^{3/2}$
• B. $K_p=\frac{2}{3^{1/2}}{p}^{1/2}$
• C. $K_p=\frac{1}{3^{2/3}}{p}^{3/2}$
• D. $K_p=\frac{1}{3^{2/3}}p$

Answer 1

The correct option is A $K_p=\frac{2}{3^{3/2}}{p}^{3/2}$

$HgO\left(s\right)\rightleftharpoons Hg\left(g\right)+\frac{1}{2}{O}_2\left(g\right)$
x x/2
$K_p=P_{Hg\left(g\right)}\times \left(P_{o_2}\right)\frac{1}{2}$
Total moles at equilibrium $=\frac{3x}{2}$
$P_{Hg}=\frac{x}{3x/2}P=\frac{2}{3}P$
$P_{o_2}=\frac{x/2}{3x/2}P=\frac{1}{3}P$
$K_p=\frac{2}{3}P{\left(\frac{1}{3}P\right)}^{1/2}=\frac{2}{3^{3/2}}{P}^{3/2}$