Question

For the equilibrium reaction $Ca{CO}_3\left(s\right)\rightleftharpoons CaO\left(s\right)+{CO}_2\left(g\right)$. The addition of more $Ca{CO}_3\left(s\right)$ causes?

• A. The decrease in the concentration of ${CO}_2\left(g\right)$
• B. The increase in the concentration of ${CO}_2\left(g\right)$
• C. No change in the concentration of ${CO}_2\left(g\right)$
• D. Increase in the concentration of $CaO\left(s\right)$

Answer 1

Answer: (C)

No change in the concentration of ${CO}_2\left(g\right)$

According to Le-Chatelier's principle, an increase in the concentration of gaseous reactants favour forward reaction that is an increase in the concentration of gaseous products.

But here the $CaC{O}_3$ is in solid form. Therefore, it will have no effect on the concentration of $C{O}_2$ (g)