For the equilibrium system 2HXg- H2g-X2gthe equilibrium constant is 1-0 - 10-5- What is the concentration of HX if the equilibrium concentration of H2 and X2 are 1-2- 10-3M- and 1-2 - 10-4M respectively-

The correct option is C 12× 10^ 2M At equilibrium ?2HX⇌1.2× 10^ 3MH_2(g)+1.2× 10^ 4MX_2(g) K=[H_2][X_2]/[HX]^2 10^ 5=1.2× 10^ 3× 1.2× 10^ 4/ ...

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Byju's Answer

Standard XII

Chemistry

Introduction

For the equil...

Question

For the equilibrium system
$2 H X (g) ⇌ H_{2} (g) + X_{2} (g)$
the equilibrium constant is $1.0 \times 10^{- 5}$ . What is the concentration of HX if the equilibrium concentration of $H_{2}$ and $X_{2}$ are $1.2 \times 10^{- 3} M$ , and $1.2 \times 10^{- 4} M$ respectively?

12 \times 10^{- 4} M

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12 \times 10^{- 3} M

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12 \times 10^{- 2} M

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12 \times 10^{- 1} M

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Solution

The correct option is C $12 \times 10^{- 2} M$
At equilibrium
$2 H X ? ⇌ H_{2} (g) 1.2 \times 10^{- 3} M + X_{2} (g) 1.2 \times 10^{- 4} M$
$K = \frac{[H_{2}] [X_{2}]}{[H X]^{2}}$
$10^{- 5} = \frac{1.2 \times 10^{- 3} \times 1.2 \times 10^{- 4}}{[H X]^{2}}$
$[H X] = \sqrt{\frac{1.2 \times 1.2 \times 10^{- 7}}{10^{- 5}}}$
$= 1.2 \times 10^{- 1}$
$= 12 \times 10^{- 2} M$

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Similar questions

2 H X (g) ⇋ H_{2} (g) + X_{2} (g); K_{C} = 1.0 \times 10^{- 5}

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32

at a given temperature.
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For the equilibrium system2HX(g)⇌H2(g)+X2(g)the equilibrium constant is 1.0×10−5. What is the concentration of HX if the equilibrium concentration of H2 and X2 are 1.2×10−3M, and 1.2×10−4M respectively?

The correct option is C 12×10−2MAt equilibrium2HX?⇌H2(g)1.2×10−3M+X2(g)1.2×10−4MK=[H2][X2][HX]210−5=1.2×10−3×1.2×10−4[HX]2[HX]=√1.2×1.2×10−710−5=1.2×10−1=12×10−2M

For the equilibrium system
$2 H X (g) ⇌ H_{2} (g) + X_{2} (g)$
the equilibrium constant is $1.0 \times 10^{- 5}$ . What is the concentration of HX if the equilibrium concentration of $H_{2}$ and $X_{2}$ are $1.2 \times 10^{- 3} M$ , and $1.2 \times 10^{- 4} M$ respectively?