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Question

For the figure shows, a rod of mass 10kg (of length 100 cm) with some point masses tied to it at different positions. Find the distance of the point (from A) at which if the rod is picked over a knife edge, it will be in equilibrium about that knife
1096199_b9349a9395f747ecb1b3b4909b8e0669.JPG

A
26.32 cm
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B
28.72 cm
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C
30.43 cm
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D
32.50 cm
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Solution

The correct option is A 26.32 cm
Let distance from A at which the knife is pricked be x cm
For Rotational equilibrium balancing torques of masses about the knife's axis we get :
20x+15(x20)=5(100x5)+7.5(100x20)
(Magnitude of Torque = Force × perpendicular distance )
On soving ,
x=26.32cm

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