Question

For the first orbit of hydrogen atom the minimum excitation potential is ____________ V.

• A. $13.6$
• B. $3.4$
• C. $10.2$
• D. $3.6$

Answer 1

Answer: (C)

$10.2$

We know that the energy of electron in hydrogen atom can be found by $\frac{-13.6}{n^2}eV$

Minimum excitation is the condition when electron is jumped from first orbit to second orbit in order to get minimum energy difference.

So, minimum excitation potential = $E_2-E_1$= $\frac{-13.6}{2^2}eV$ - $\frac{-13.6}{1^2}eV$

$\Rightarrow E.P=-3.4-(-13.6)$

$\Rightarrow E.P=10.2$

Therefore, C is correct option.