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Standard XII

Chemistry

Enthalpy

For the first...

Question

For the first order reaction A forms P, the temperature (T) dependent rate constant (k) was found to follow the equation
log k = -(2000)1/T +60 . The pre-exponential factor A and the activation energy E_a, respectively are
( IIT 2009)

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Solution

Given, log K = 6 - 2000/T

On comparing it with our standard equation , we have,

Since, log K = log A - Ea/2.303RT So, A = 106 sec-1 and Ea = 38.3 kJ/mole

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For the first order reaction A forms P, the temperature (T) dependent rate constant (k) was found to follow the equation log k = -(2000)1/T +60 . The pre-exponential factor A and the activation energy Ea, respectively are ( IIT 2009)

Given, log K = 6 - 2000/T On comparing it with our standard equation , we have, Since, log K = log A - Ea/2.303RT So, A = 106 sec-1 and Ea = 38.3 kJ/mole

For the first order reaction A forms P, the temperature (T) dependent rate constant (k) was found to follow the equation
log k = -(2000)1/T +60 . The pre-exponential factor A and the activation energy E_a, respectively are
( IIT 2009)

Given, log K = 6 - 2000/T

On comparing it with our standard equation , we have,

Since, log K = log A - Ea/2.303RT So, A = 106 sec-1 and Ea = 38.3 kJ/mole