For the first order reaction A→2B, 1mole of reactant A gives 0.2 moles of B after 100 minutes. The half life of the reaction in min (nearest integer) is :
Take ln2=0.693,ln3=1.1ln10=2.3
A
658
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B
658.00
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C
658.0
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Solution
A→2B t=010 t=100min1−x2x
Given: 2x=0.2⇒x=0.1
k=1tln[A]0[A] [A0] is the initial concentration [A] is the final concentration at time t