For the following balanced equation :

$a F e^{2 +} + b C r_{2} O_{7}^{2 -} + c H^{+} ⟶ d F e^{3 +} + e C r^{3 +} +$ f $H_{2} O$

The value of a+b+c+d+e+f is :
36

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Solution

The correct option is A 36
On balancing the equation we get:
$6 F e^{2 +} + C r_{2} O_{7}^{2 -} + 14 H^{+} ⟶ 6 F e^{3 +} + 2 C r^{3 +}$ + $7 H_{2} O$
So,
a+b+c+d+e+f = 36.

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For the following balanced equation : aFe2++bCr2O2−7+cH+⟶dFe3++eCr3++ fH2O The value of a+b+c+d+e+f is :36

The correct option is A 36On balancing the equation we get: 6Fe2++Cr2O2−7+14H+⟶6Fe3++2Cr3++7H2O So, a+b+c+d+e+f = 36.

For the following balanced equation :

$a F e^{2 +} + b C r_{2} O_{7}^{2 -} + c H^{+} ⟶ d F e^{3 +} + e C r^{3 +} +$ f $H_{2} O$

The value of a+b+c+d+e+f is :
36

The correct option is A 36
On balancing the equation we get:
$6 F e^{2 +} + C r_{2} O_{7}^{2 -} + 14 H^{+} ⟶ 6 F e^{3 +} + 2 C r^{3 +}$ + $7 H_{2} O$
So,
a+b+c+d+e+f = 36.