For the following cell-reaction,

$C u (s) + 2 A g^{+} (a q) \to 2 A g (s) + C u^{2 +} (a q)$ .

$E_{c e l l}$ is $0.46 V$ at $300 K$ and $0.48 V$ at $310 K$

The temperature coefficient of the e.m.f of the cell in above questions is:

0.02 V K^{- 1}

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0.2 V K^{- 1}

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0.002 V K^{- 1}

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2 V K^{- 1}

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Solution

The correct option is C $0.002 V K^{- 1}$
In this question, EMF increases with increase in temperature, i,e. $(\frac{δ E}{δ T})_{P}$ is positive.

Therefore,
Temperature coefficient, $(\frac{δ E}{δ T})_{P} = \frac{0.48 - 0.46}{310 - 300} = \frac{0.02}{10} = 0.002 V K^{- 1}$

The correct answer is option C.

Suggest Corrections

Similar questions

C u (s) + 2 A g^{+} (a q .) \to C u^{2 +} (a q .) + 2 A g (s)

E_{c e l l}^{\circ} = 0.46 V

C u^{2 +}, E_{c e l l}^{\circ}

C u (s) + 2 {A g}^{+} (a q) \to {C u}^{2 +} (A q) + 2 A g (s)

(K)

E_{c e l l}^{\circ} = 0.46 V

Calculate the equilibrium constant of the reaction.
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$ , $E_{c e l l}^{⊖} = 0.46 V$

C u (s) + 2 A g^{+} (a q) ⇌ C u^{2 +} (a q) + 2 A g (s)

E^{\circ} = 0.46 V

298 K

C u (s) + 2 {A g}^{+} (a q) ⟶ {C u}^{2 +} (a q) + 2 A g (s)

E^{o} = 0.46 V

298 K

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