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Question

For the following cell,
Zn(s)|ZnSO4(aq)CuSO4(aq)|Cu(s)
When the concentration of Zn2+ is 10 times the concentration of Cu2+, the expression for the G (in Jmol1) is: [F is Faraday constant; R is gas constant; T is temperature; E(cell)=1.1V]

A
2.303RT+1.1F
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B
2.303R2.2F
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C
1.1F
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D
2.2F
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Solution

The correct option is B 2.303R2.2F
Overall reaction:
Zn+Cu2+(aq)Zn2+(aq)+Cu
we know that,
E=ERTnFln[Zn2+][Cu2+]
E=1.1RT2Fln10
Now, ΔG=nFE
Here n=2
G=2F[1.1RT2Fln10]
=2.2F+RTlog1010×2.303
G=2.303RT2.2F

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