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Byju's Answer
Standard XII
Chemistry
Heat of Reaction
For the follo...
Question
For the following data calculate lattice energy of
A
B
(
s
)
?
A
(
s
)
→
A
+
(
g
)
+
e
−
610
k
J
/
m
o
l
B
(
s
)
+
e
→
B
−
(
g
)
+
−
260
k
J
/
m
o
l
A
(
s
)
+
B
(
g
)
→
A
B
(
s
)
−
−
569
k
J
/
m
o
l
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Solution
Δ
H
F
=
Δ
H
1
s
u
l
s
+
Δ
H
2
s
u
b
+
I
E
+
E
A
+
L
E
⟹
−
569
=
−
610
+
260
+
L
E
⟹
L
E
=
−
219
k
J
/
m
o
l
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Similar questions
Q.
If
A
(
s
)
→
A
+
(
g
)
+
e
...................600 kJ/mol
B
2
(
g
)
+
e
→
B
−
(
g
)
......................260kJ/mol
A
(
s
)
+
B
2
(
g
)
→
A
B
(
s
)
...............-550kJ/mol
The lattice energy of
A
B
(
s
)
Will be:
Q.
From the following sequence calculate the lattice energy of AB(s):
A
(
s
)
→
A
(
g
)
+
e
;
610
k
J
m
o
l
−
1
B
(
g
)
+
e
→
B
(
g
)
;
−
260
k
J
m
o
l
−
1
A
(
s
)
+
B
(
g
)
→
A
B
(
s
)
;
−
569
k
J
m
o
l
−
1
Q.
Use the following data to calculate second electron affinity of oxygen for the process
O
−
(
g
)
+
e
−
(
g
)
→
O
2
−
(
g
)
.
Heat of sublimation of
M
g
(
s
)
=
147.7
k
J
/
m
o
l
Ionisation energy of
M
g
(
g
)
to form
M
g
2
+
(
g
)
=
2189
k
J
/
m
o
l
Bond dissociation energy for
O
2
=
498.4
k
J
/
m
o
l
First electron affinity of
O
(
g
)
=
−
141
k
J
/
m
o
l
Heat formation of
M
g
O
(
s
)
=
−
601.7
k
J
/
m
o
l
lattice energy of
M
g
O
=
−
3791
k
J
/
m
o
l
Q.
Use the following data to calculate second electron affinity of oxygen for the process
O
−
(
g
)
+
e
−
(
g
)
→
O
2
−
(
g
)
.
Heat of sublimation of
M
g
(
s
)
=
147.7
kJ/mol
Ionisation energy of
M
g
(
g
)
to form
M
g
2
+
(
g
)
=
2189
kJ/mol
Bond dissociation energy for
O
2
=
498.4
kJ/mol
First electron affinity of
O
(
g
)
=
−
141
kJ/mol
Heat formation of
M
g
O
(
s
)
=
−
601.7
kJ/mol
lattice energy of
M
g
O
=
−
3791
kJ/mol
Q.
Calculate the enthalpy of formation of
M
g
F
2
from the following data-
Enthalpy of sublimation for
M
g
(
s
)
→
M
g
(
g
)
=
146.4
k
J
m
o
l
−
1
Enthalpy of dissociation of
F
2
(
g
)
→
2
F
(
g
)
=
155.8
k
J
m
o
l
−
1
Ionisation energy of
M
g
(
g
)
→
M
g
2
+
(
g
)
=
2186
k
J
m
o
l
−
1
Electron gain enthalpy of
2
F
→
2
F
−
1
=
2
×
−
322.6
=
−
645.2
k
J
m
o
l
−
1
Lattice enthalpy of
M
g
F
2
=
−
2922.5
k
J
m
o
l
−
1
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