For the following data, mean of x is found to be 7.3. The missing frequency is
x : 5 6 7 8 9
f : 4 6 12 - 8

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Solution

The correct option is A 10
$M e a n = \frac{5 \times 4 + 6 \times 6 + 7 \times 12 + 8 \times f + 9 \times 8}{4 + 6 + 12 + f + 8}$
Where f is the missing frequency
$\Rightarrow 7.3 = \frac{20 + 36 + 84 + 8 f + 72}{30 + f} = \frac{212 + 8 f}{30 + f} \Rightarrow 219 + 7.3 f = 218 + 8 f \Rightarrow 7 = .7 f \Rightarrow f = \frac{7}{.7} = \frac{70}{7} = 10$

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Similar questions

For the following data, mean of x is found to be 7.3. The missing frequency is
x : 5 6 7 8 9
f : 4 6 12 - 8

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$\begin{matrix} Class interval & 0 - 10 & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 & 50 - 60 & 60 - 70 & 70 - 80 Frequency & 7 & 10 & x & 13 & y & 10 & 14 & 9 \end{matrix}$

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For the following data, mean of x is found to be 7.3. The missing frequency is x : 5 6 7 8 9 f : 4 6 12 - 8

The correct option is A 10Mean=5×4 + 6×6 + 7×12 + 8×f + 9×84 + 6 + 12 + f + 8 Where f is the missing frequency ⇒7.3=20 + 36 + 84 + 8f + 7230 + f=212+8f30+f⇒219+7.3f=218+8f⇒7=.7f⇒f=7.7=707=10

For the following data, mean of x is found to be 7.3. The missing frequency is
x : 5 6 7 8 9
f : 4 6 12 - 8